Chelsea can do better: Andre Schurrle
Chelsea midfielder believes his side can move up a gear when they take on newcomers Leicester tonight
London: Jose Mourinho's Chelsea side will attempt to apply early pressure on their main Premier League rivals when they face a newly-promoted side for the second time inside a week with the visit of Leicester City to Stamford Bridge today.
Andre Schurrle celebrates after scoring for Chelsea against Burnley at Turf Moor on Monday. Pic/Getty Images
Mourinho's team started their campaign with a comfortable 3-1 victory at Burnley that included a goal for recent signing Diego Costa.
And it would constitute a major surprise if they failed to take maximum points against Nigel Pearson's City side.
The performances of Costa and Cesc Fabregas, another major close-season signing, offered promising signs that Mourinho's efforts to strengthen his side's attacking options have been successful.
But Andre Schurrle, fresh from his success with Germany at the World Cup in Brazil and the scorer of Chelsea's second goal at Turf Moor, insists there is more to come from himself and the rest of the team.
'More to come'
"I think it was a good start for me, but of course we can be better. And when I am 100 percent fit, there will be more," Schurrle said.
"So there's a lot of work for me, but I'm feeling good. I'm enjoying my game, I'm enjoying being on the pitch. I think the whole team played well at Burnley. We had a lot of control, passes, good combinations. It was a lot of fun on the pitch."
Thibaut Courtois will again start in goal having been selected ahead of long term number one Petr Cech at Burnley, a decision that has raised doubts about Cech's long-term future at Chelsea.
Mourinho must decide whether to hand a debut to newly arrived left-back Filipe Luis after starting with Cesar Azpilicueta in the opening game.
Meanwhile, Leicester boss Nigel Pearson has problems with midfielders Danny Drinkwater (hamstring) and Matty James (shin) ruled out but striker Jamie Vardy and winger Marc Albrighton should be available.