The third-seeded De Minaur won his eighth ATP title to become the fourth player to repeat as champion in Mexico, the first since David Ferrer in 2010-12
Australia’s Alex De Minaur celebrates with the trophy in Acapulco on Saturday. Pic/AFP
Alex De Minaur beat Casper Rudd 6-4, 6-4 on Saturday to become the first player to win back-to-back titles in the Mexican Open since 2012.
The third-seeded De Minaur won his eighth ATP title to become the fourth player to repeat as champion in Mexico, the first since David Ferrer in 2010-12.
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The 25-year-old Australian won his 10 consecutive matches in Acapulco to break a four-match losing streak in ATP finals, including Rotterdam earlier this year.
“Acapulco is becoming like a second home. I thought that it was impossible to get feel better after what happened last year, but I came back a year later to defend the title and it has been true pleasure,” De Minaur said.
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